AQA GCSE Physics

Forces & Motion

A force is invisible; the change it causes is the evidence it leaves behind.

Turn pushes, pulls and motion into vectors, graphs and equations. Follow the resultant force, connect work to energy, and use changes in velocity or momentum to explain what the object does next.

  • Draw the force story before calculating
  • Read gradients and areas with their units
  • Separate mass, weight, speed and velocity
  • 11 illustrated pages
  • Examva Pro
  • Combined & Separate
  • Foundation & Higher

Your revision route

What you’ll learn

  • Distinguish scalars from vectors and classify contact and non-contact forces.
  • Calculate weight and resultant force, and apply force diagrams with explicit Higher Tier labels.
  • Explain work and deformation, use spring equations, and evaluate the force–extension practical.
  • Separate Physics only: analyse moments, levers, gears, fluid pressure and atmospheric pressure.
  • Distinguish distance, displacement, speed and velocity, and recall suitable typical speeds.
  • Interpret distance–time and velocity–time graphs and calculate speed, acceleration and displacement.
  • Apply Newton's three laws and plan the required practical linking force, mass and acceleration.
  • Explain thinking and braking distances using reaction time, road conditions, vehicle condition and energy transfer.
  • Higher Tier: calculate momentum and apply its conservation; label separate-Physics momentum-change content.

Build the big picture

Key ideas

Forces are interactions with direction attached

A force is not a possession tucked inside an object; it is a push or pull produced when two objects interact.

  • Contact forces include friction, drag, tension and normal contact force. Gravitational, electrostatic and magnetic forces act without contact.
  • Force is a vector: an arrow's direction shows the force direction and its length can represent magnitude.
  • Weight is W = mg and acts through the centre of mass. At fixed g it is directly proportional to mass and is measured with a calibrated newtonmeter.
  • Replace forces along one straight line with a single resultant, keeping opposing directions and signs clear.

The punchline: Name the interacting objects, draw directions, then combine the forces.

Higher Tier: make several forces tell one story

A free-body diagram clears the scenery away and leaves only the forces acting on the chosen object.

  • Draw each force from the object, label it, and use arrow direction and length to show its vector character.
  • Balanced forces give zero resultant; they do not prove the object is stationary—it may move with constant velocity.
  • Resolve one force into perpendicular components, or use a scale vector diagram to find a resultant's magnitude and direction.
  • Check that your resultant would cause the described change in speed or direction.

The punchline: Choose the object first; only forces acting on that object belong on its diagram.

A force earns work only by causing displacement

Push a wall that never moves and the equation awards no mechanical work; move an object along the force and energy is transferred.

  • Work done is force multiplied by distance moved along the force's line of action. One joule equals one newton-metre.
  • Work against friction transfers energy into thermal stores, so the surfaces warm rather than energy disappearing.
  • Stretching, bending or compressing a stationary object needs more than one force. Up to the limit of proportionality, F = ke.
  • Elastic deformation reverses; inelastic does not fully reverse. Before inelastic deformation, work done on a spring equals its elastic energy increase.

The punchline: Use displacement along the force, and state the energy store that changes.

A graph operation becomes a physical quantity

The axes determine what a gradient or area means. Use the units as a built-in check before interpreting the shape as motion.

  • Distance–time gradientChange in distance divided by change in time gives speed in m/s. A horizontal line means stationary.
  • Velocity–time gradientChange in velocity divided by change in time gives acceleration in m/s².
  • Velocity–time areaHigher Tier: signed area under the graph gives displacement in metres; area below the axis is negative.
Gradient is rise ÷ run. Area is base × height for simple sections; split a compound journey into manageable shapes.

Separate Physics only: distance gives a force leverage

A door handle sits far from the hinge for a reason: the same force creates a larger turning effect farther from the pivot.

  • Moment = force × perpendicular distance from the pivot to the force's line of action.
  • For balance, total clockwise moment equals total anticlockwise moment about the same pivot.
  • Levers transmit and can multiply turning effects; meshed gears transmit rotation, reverse direction and trade turning force against speed.
  • Use the perpendicular distance, not the sloping length of a lever or spanner.

The punchline: Locate the pivot and line of action before measuring the moment arm.

Separate Physics only: fluids push at right angles

A fluid's restless particles create pressure, and pressure acts normal to every surface it meets.

  • Pressure is normal force divided by area. The same force spread over a larger area produces a smaller pressure.
  • HT only: liquid pressure p = hρg rises with depth and density; greater pressure below a submerged object can create upward resultant force, or upthrust.
  • Floating occurs when upthrust balances weight. If weight is greater than upthrust, the object accelerates downwards.
  • Atmospheric pressure comes from air-particle collisions and decreases with altitude because fewer air molecules lie above and the air is less dense.

The punchline: For fluid questions, connect particle collisions or liquid weight to pressure, then pressure to force.

The missing direction changes the quantity

Walk five metres east and five metres west: your distance is ten metres, but your displacement is zero.

  • Distance and speed are scalars. Displacement and velocity are vectors, so they require direction as well as magnitude.
  • Velocity is speed in a stated direction. HT only: circular motion can have constant speed but changing velocity because direction continually changes.
  • Typical values are about 1.5 m/s walking, 3 m/s running, 6 m/s cycling and 330 m/s for sound in air; real values vary with conditions.
  • For constant speed use s = vt; otherwise use total distance divided by total time. Direct measurements of distance and time give speed.

The punchline: If direction matters, use displacement or velocity and state that direction.

Make the model move

Interactive checkpoint

Touch the science. Change a state, build a route or test a relationship.

Read the journey

Decode states on a velocity–time graph

Select a graph state. Use position relative to the time axis for direction and gradient for acceleration before deciding whether the object is speeding up.

Zero velocity means stationary at that instant

If the line remains on the axis, the object stays stationary. Crossing the axis means it stops momentarily and reverses direction.

1 of 5 states explored

Velocity supplies direction as well as speed. An object speeds up when velocity and acceleration share a sign, and slows when their signs oppose.

Turn two dials

Explore resultant force with F = ma

Change mass and acceleration magnitude. Double either input while holding the other fixed and watch the required resultant force double.

F = m × a

100 kg2000 kg
kg
0.5 m/s²10 m/s²
m/s²

Resultant force magnitude2,000 N

F = ma uses the resultant force. The calculator gives its magnitude; its direction matches the acceleration, while individual forces may be larger and oppose one another.

A graph can be a journey folded flat

On a motion graph, a slope is not decoration: it is a physical rate whose units tell you what it means.

  • The gradient of a distance–time graph is speed; a horizontal section means stationary and a steeper section means faster motion.
  • HT only: draw a tangent to a curved distance–time graph to estimate speed at one instant.
  • The gradient of a velocity–time graph is acceleration. A negative gradient means velocity is becoming more negative or less positive—not automatically slowing.
  • HT only: the signed area under a velocity–time graph gives displacement; count squares where necessary.

The punchline: Name the axes, calculate the units of gradient or area, then interpret the motion.

Acceleration measures how quickly velocity changes

An object can accelerate by speeding up, slowing down or turning, because velocity includes direction.

  • Average acceleration is change in velocity divided by time. For uniform acceleration, use v² − u² = 2as when time is absent.
  • Near Earth's surface, free-fall acceleration is about 9.8 m/s² before air resistance becomes important.
  • A falling object accelerates while weight exceeds drag. As speed and drag rise, the resultant shrinks; at zero resultant it reaches terminal velocity.
  • Separate Physics only: draw and interpret velocity–time graphs for objects reaching terminal velocity.

The punchline: Track how both forces and velocity change through the fall.

Newton's laws connect interactions to changing motion

The resultant force is the editor of velocity: zero leaves it unchanged; non-zero rewrites its speed, direction or both.

  • First law: zero resultant keeps an object at rest or moving at constant velocity. A steady vehicle has driving and resistive forces balanced.
  • Second law: F = ma. At fixed mass, a ∝ F; at fixed force, a ∝ 1/m. Use ~ when a transport force or acceleration is only an estimate.
  • Third law: interacting objects exert equal and opposite forces on each other. The pair acts on different objects, so it does not cancel on one object.
  • HT only: inertia is resistance to changing velocity; inertial mass = force/acceleration.

The punchline: Separate balanced forces on one object from a third-law pair on two objects.

From interaction to changing motion

A force answer becomes precise when it follows the complete causal chain instead of jumping from one arrow to a final speed.

  1. InteractionsIdentify which objects push or pull the chosen object.
  2. Force vectorsDraw each force with magnitude and direction, then combine them.
  3. Resultant forceThe vector total may be zero or point in a particular direction.
  4. AccelerationA non-zero resultant produces acceleration in its direction; F = ma sets the magnitude.
  5. Velocity changeAcceleration changes speed, direction or both. Zero resultant leaves velocity constant.
Balanced forces mean constant velocity, not necessarily no motion. Third-law partner forces act on different objects.

Stopping begins before the brakes do

During reaction time the vehicle keeps moving, so a distracted driver spends road before braking has even started.

  • Stopping distance = thinking distance + braking distance. Typical human reaction times are about 0.2–0.9 s.
  • Tiredness, alcohol, drugs and distractions can increase reaction time; measure it with repeated ruler-drop or computer tests and examine variation.
  • Wet or icy roads and worn tyres or brakes reduce effective braking. Greater starting speed means more kinetic energy must be transferred.
  • Large braking forces can overheat brakes, reduce control and increase injury risk. Separate Physics: interpret stopping graphs; HT: estimate road forces.

The punchline: Link each factor to thinking distance, braking distance or both—never just list it.

Higher Tier: momentum keeps the event's accounts

In a closed system, a collision can redistribute momentum dramatically while the signed total stays unchanged.

  • Momentum p = mv is a vector, so choose a positive direction and give opposite velocities negative signs.
  • For both routes, total momentum before equals total momentum after in a closed system; Combined Science requires qualitative use of collision examples.
  • Separate Physics only: complete collision calculations using conservation of momentum.
  • Separate Physics HT only: F = Δp/Δt. Increasing stopping time reduces force for the same momentum change, explaining airbags, helmets and crash mats.

The punchline: Set a direction, total the momentum before, then balance the signed total after.

Words worth knowing

Key definitions

scalar quantity
A quantity with magnitude only, such as distance, speed, mass or time.
vector quantity
A quantity with magnitude and direction, such as force, displacement, velocity, acceleration or momentum.
resultant force
The single force that has the same effect as all forces acting on an object together.
weight
The gravitational force acting on an object, measured in newtons.
centre of mass
The single point through which an object's weight may be considered to act.
work done
Energy transferred when a force causes displacement along its line of action.
elastic deformation
A change of shape that reverses when the force is removed.
inelastic deformation
A change of shape that does not fully reverse when the force is removed.
limit of proportionality
The point beyond which force and extension are no longer directly proportional.
moment
The turning effect of a force about a pivot, measured in newton-metres.
pressure
The normal force acting per unit area, measured in pascals.
upthrust
The upward resultant force on an object in a fluid caused by greater pressure on its lower surface.
distance
The total length of the route travelled, without direction.
displacement
The straight-line change in position from start to finish, including direction.
velocity
Speed in a given direction.
acceleration
The rate of change of velocity, measured in metres per second squared.
terminal velocity
Constant velocity reached when resistive forces balance weight and the resultant force is zero.
inertia
The tendency of an object to remain at rest or continue at constant velocity.
stopping distance
Thinking distance plus braking distance.
momentum
A vector property of a moving object equal to mass multiplied by velocity.

Calculate with confidence

Equations

Weight

W = m × g

Weight equals mass multiplied by gravitational field strength.

Symbols used in Weight
SymbolMeaningUnit
WweightN
mmasskg
ggravitational field strengthN/kg

Exam tip: Weight is a force in newtons; mass is not measured in newtons.

Work done

W = F × s

Work done equals force multiplied by distance moved along the force's line of action.

Symbols used in Work done
SymbolMeaningUnit
Wwork doneJ
FforceN
sdistance along line of actionm

Exam tip: One joule equals one newton-metre; use distance moved along the force, not any unrelated path length.

Force and extension

F = k × e

Up to the limit of proportionality, force equals spring constant multiplied by extension or compression.

Symbols used in Force and extension
SymbolMeaningUnit
FforceN
kspring constantN/m
eextension or compressionm

Exam tip: Extension is stretched length minus original length, converted to metres.

Elastic potential energy

Eₑ = 1/2 × k × e²

Energy stored by an elastically deformed spring before the limit of proportionality is exceeded.

Symbols used in Elastic potential energy
SymbolMeaningUnit
Eₑelastic potential energyJ
kspring constantN/m
eextension or compressionm

Exam tip: This equation is given on the equation sheet; square the extension in metres.

Separate Physics only: moment

M = F × d

The moment equals force multiplied by perpendicular distance from pivot to line of action.

Symbols used in Separate Physics only: moment
SymbolMeaningUnit
MmomentN m
FforceN
dperpendicular distancem

Exam tip: Measure to the force's line of action at 90°, not simply to the point where the force is applied.

Separate Physics only: pressure

p = F / A

Pressure equals the force normal to a surface divided by its area.

Symbols used in Separate Physics only: pressure
SymbolMeaningUnit
ppressurePa
Fnormal forceN
Asurface area

Exam tip: Convert areas such as cm² to m² before calculating pressure in pascals.

Separate Physics HT only: liquid pressure

p = h × ρ × g

Pressure due to a liquid column depends on its height, density and gravitational field strength.

Symbols used in Separate Physics HT only: liquid pressure
SymbolMeaningUnit
ppressure due to liquidPa
hheight of liquid columnm
ρliquid densitykg/m³
ggravitational field strengthN/kg

Exam tip: This equation is given; use vertical depth below the surface for h.

Distance at constant speed

s = v × t

For constant speed, distance travelled equals speed multiplied by time.

Symbols used in Distance at constant speed
SymbolMeaningUnit
sdistancem
vspeedm/s
ttimes

Exam tip: For non-uniform motion, average speed uses total distance divided by total time.

Average acceleration

a = Δv / t

Average acceleration equals change in velocity divided by time taken.

Symbols used in Average acceleration
SymbolMeaningUnit
aaverage accelerationm/s²
Δvchange in velocitym/s
ttimes

Exam tip: Calculate Δv as final velocity minus initial velocity, including signs.

Uniform acceleration without time

v² − u² = 2 × a × s

For uniform acceleration, final and initial velocities link to acceleration and displacement.

Symbols used in Uniform acceleration without time
SymbolMeaningUnit
vfinal velocitym/s
uinitial velocitym/s
aaccelerationm/s²
sdisplacementm

Exam tip: This equation is given and applies only to uniform acceleration; square both velocity values.

Newton's Second Law

F = m × a

Resultant force equals mass multiplied by acceleration.

Symbols used in Newton's Second Law
SymbolMeaningUnit
Fresultant forceN
mmasskg
aaccelerationm/s²

Exam tip: Use the resultant force, not one force selected from the diagram.

Higher Tier: momentum

p = m × v

Momentum equals mass multiplied by velocity and therefore includes direction.

Symbols used in Higher Tier: momentum
SymbolMeaningUnit
pmomentumkg m/s
mmasskg
vvelocitym/s

Exam tip: Choose a positive direction and use a negative velocity for motion in the opposite direction.

Separate Physics HT only: force and momentum change

F = m × Δv / Δt = Δp / Δt

Force equals the rate of change of momentum for a constant-mass object.

Symbols used in Separate Physics HT only: force and momentum change
SymbolMeaningUnit
FforceN
mmasskg
Δvchange in velocitym/s
Δttime for the changes
Δpchange in momentumkg m/s

Exam tip: This equation is given; for the same Δp, a longer stopping time means a smaller average force.

Follow it step by step

Processes to remember

How to analyse the forces on an object

  1. Choose the object or system and list only interactions that exert forces on it.
  2. Draw and label the force directions; at Higher Tier, use a free-body diagram and suitable arrow lengths.
  3. Combine forces along each line, assigning opposite directions opposite signs.
  4. If the resultant is zero, predict rest or constant velocity; if it is non-zero, predict a change in velocity.
  5. Use F = ma when numerical mass and acceleration information is available.

Exam tip: A third-law partner force acts on the other object, so do not add it to this object's resultant.

How to decode a motion graph

  1. Read both axes and their units before describing any section.
  2. For distance–time, use gradient for speed; at Higher Tier use a tangent for instantaneous speed on a curve.
  3. For velocity–time, use gradient for acceleration and, at Higher Tier, signed area for displacement.
  4. Split a journey into straight or curved sections and explain each in ordinary motion language.
  5. Check that your calculated gradient or area has the expected physical unit.

Exam tip: A horizontal distance–time line means stopped; a horizontal velocity–time line means constant velocity.

How to explain a stopping-distance factor

  1. State whether the factor changes reaction time, grip, braking force, starting speed or vehicle condition.
  2. Link reaction time or speed to the distance travelled before braking begins.
  3. Link grip and vehicle condition to braking force and braking distance.
  4. For speed, explain that greater kinetic energy requires more work by the brakes to transfer it.
  5. Finish with the effect on thinking distance, braking distance or total stopping distance.

Exam tip: A named factor alone is not an explanation; show the causal chain to distance.

Higher Tier: how to solve a momentum event

  1. Choose one direction as positive and assign signs to every velocity.
  2. Calculate each object's momentum before using p = mv and add the signed values.
  3. For a closed system, set total momentum after equal to total momentum before.
  4. Insert known final momenta, solve for the unknown and state its direction.
  5. Separate Physics HT only: use F = Δp/Δt when force or collision time is required.

Exam tip: Momentum is conserved as a signed total, not as a list of positive speeds.

See the thinking

Worked example

Worked example: from motion to force to work

A 1,200 kg car accelerates uniformly in a straight line from 10 m/s to 20 m/s over 75 m. Calculate its acceleration, resultant force and work done by that resultant force.

  1. Use v² − u² = 2as: 20² − 10² = 2 × a × 75.
  2. Solve for acceleration: 300 = 150a, so a = 2.0 m/s².
  3. Use F = ma: F = 1,200 × 2.0 = 2,400 N.
  4. Use W = Fs: W = 2,400 × 75 = 180,000 J.
  5. Convert the final energy transfer: 180,000 J = 180 kJ.

Answer: The acceleration is 2.0 m/s², the resultant force is 2,400 N and the work done is 180 kJ.

The question states uniform acceleration, so the equation without time is valid. Because the force is the resultant along the displacement, its work matches the car's kinetic-energy increase when other energy changes are ignored.

Protect the marks

Common mistakes

Watch out: Using mass and weight as interchangeable words.

Do this instead: Mass is measured in kilograms; weight is the gravitational force W = mg in newtons.

Watch out: Assuming zero resultant force means an object must be stationary.

Do this instead: It may be stationary or moving at constant velocity.

Watch out: Putting both forces in a third-law pair on one free-body diagram.

Do this instead: Equal-and-opposite interaction forces act on different objects.

Watch out: Using a spring's total length as its extension.

Do this instead: Extension equals stretched length minus original length, converted to metres.

Watch out: Measuring a moment arm along a sloping lever.

Do this instead: Separate Physics only: use the perpendicular distance from pivot to line of action.

Watch out: Treating distance and displacement as identical.

Do this instead: Distance follows the route; displacement is the straight-line change with direction.

Watch out: Reading every graph gradient as speed.

Do this instead: Distance–time gradient is speed; velocity–time gradient is acceleration.

Watch out: Calling any negative acceleration deceleration.

Do this instead: An object slows only when acceleration opposes its velocity; signs depend on the chosen direction.

Watch out: Saying heavier objects always fall faster in free fall.

Do this instead: Without air resistance, objects near Earth share about 9.8 m/s² acceleration regardless of mass.

Watch out: Saying speed alone causes a long thinking distance.

Do this instead: Thinking distance depends on speed and reaction time; explain how the named factor changes one or both.

Watch out: Adding momentum magnitudes without directions.

Do this instead: Higher Tier: choose a positive direction and add signed momenta.

Plan it like the exam

Required practicals

Investigate force and extension of a spring

Combined Science and separate Physics

Aim: Measure how a spring's extension changes with applied force and determine its spring constant in the linear region.

Method

  1. Clamp the spring securely beside a vertical ruler and record its unloaded length at eye level.
  2. Add a known mass, allow oscillations to stop, record the new length and calculate extension.
  3. Calculate applied force from F = mg using the total hanging mass.
  4. Increase force in equal steps without exceeding the teacher-set safe limit, recording force and extension each time.
  5. Repeat readings and unload the spring to check whether it returns to its original length.
  6. Plot force vertically against extension horizontally and find the gradient of the straight-line region.

Variables

Independent
force applied to the spring
Dependent
extension of the spring
Controls
  • same spring and ruler position
  • starting reference point
  • gravitational field strength
  • reading method

Analysis: A straight line through the origin supports F ∝ e. For force plotted against extension, gradient = spring constant k. Curvature marks departure from proportionality; failure to return indicates inelastic deformation.

Safety

  • Secure the stand with a heavy base and keep feet clear of falling masses.
  • Wear eye protection and do not overstretch the spring.
  • Add or remove masses only when the spring is steady.

Improvements

  • Use a pointer and read the ruler at eye level to reduce parallax.
  • Take smaller force intervals near the limit of proportionality.
  • Repeat loading and unloading measurements and use a best-fit line.

Investigate force, mass and acceleration

Combined Science and separate Physics

Aim: Test how acceleration changes with force at constant mass and with mass at constant force.

Method

  1. Set a trolley on a level runway connected over a pulley to a hanging mass, with light gates or a motion sensor measuring acceleration.
  2. To vary force at constant total mass, transfer slotted masses from the trolley to the hanger and record acceleration for each driving force.
  3. Repeat each force setting, calculate a mean acceleration and keep the trolley-plus-hanger system's total mass constant.
  4. To vary mass at constant force, keep the hanging mass fixed and add masses to the trolley.
  5. Measure repeated accelerations for each total mass while keeping the runway, release point and driving force unchanged.
  6. Plot acceleration against force, then acceleration against reciprocal mass for the second investigation.

Variables

Independent
driving force in the first investigation; total accelerated mass in the second
Dependent
acceleration of the trolley system
Controls
  • total mass while varying force
  • driving force while varying mass
  • runway slope and surface
  • release point and measuring equipment

Analysis: At constant mass, acceleration should rise linearly with resultant force. At constant force, acceleration falls as mass rises; plotting a against 1/m should be linear. Friction can create a non-zero intercept.

Safety

  • Use a stop block so the trolley cannot leave the runway.
  • Keep feet clear of the hanging masses and use only a teacher-approved load.
  • Keep fingers, hair and loose clothing away from the moving trolley and pulley.

Improvements

  • Level the runway and estimate or compensate for friction consistently.
  • Use light gates or a motion sensor rather than hand timing.
  • Repeat each setting and test a wider sensible range of force and mass.

Try it before you move on

Quick check

Say your answer first, then open the card to check it.

Calculate the weight of a 2.0 kg object where g = 9.8 N/kg.

Answer: 19.6 N

W = mg = 2.0 × 9.8 = 19.6 N.

A 12 N force acts east and a 7 N force acts west. What is the resultant?

Answer: 5 N east

The forces oppose, so subtract their magnitudes and keep the direction of the larger force.

A spring has k = 20 N/m and extends by 0.050 m. What force is applied?

Answer: 1.0 N

F = ke = 20 × 0.050 = 1.0 N.

A distance–time graph rises by 50 m in 10 s along a straight section. What is the speed?

Answer: 5.0 m/s

Speed is the gradient: 50/10 = 5.0 m/s.

Velocity changes from 4 m/s to 10 m/s in 3 s. What is the average acceleration?

Answer: 2.0 m/s²

a = Δv/t = (10 − 4)/3 = 2.0 m/s².

Separate Physics only: a 30 N force acts 0.20 m perpendicularly from a pivot. Find the moment.

Answer: 6.0 N m

M = Fd = 30 × 0.20 = 6.0 N m.

Which part of stopping distance is increased directly by a longer reaction time?

Answer: Thinking distance

The vehicle continues moving before the brakes are applied, so it travels farther during the driver's reaction.

Higher Tier: what is the momentum of a 500 kg object moving at 4 m/s east?

Answer: 2,000 kg m/s east

p = mv = 500 × 4 = 2,000 kg m/s; momentum includes the eastward direction.

Good questions, clear answers

Frequently asked questions

What is the difference between mass and weight?

Mass measures how much matter an object contains and is measured in kilograms. Weight is the gravitational force on that mass, measured in newtons, so it changes when gravitational field strength changes.

Can an object move when the resultant force is zero?

Yes. Newton's First Law says zero resultant means constant velocity, which includes staying at rest or moving at constant speed in a straight line.

Why do third-law forces not cancel each other?

They are equal and opposite but act on different objects. Forces can cancel in one object's resultant only when those forces act on that same object.

How do I know whether a graph's area or gradient matters?

Use the axes and units. On distance–time graphs, gradient gives speed. On velocity–time graphs, gradient gives acceleration and, at Higher Tier, signed area gives displacement.

Does terminal velocity mean there are no forces?

No. Weight and resistive forces still act, but they balance, making the resultant zero. The object therefore continues at constant velocity.

Why does speed increase braking distance?

A faster vehicle has more kinetic energy. The brakes must transfer more energy through work against friction, so with comparable braking conditions a greater distance is needed.

When is momentum conserved?

At Higher Tier, treat total momentum as conserved in a closed system where no external resultant force changes the system's momentum during the event. Include direction by using signed velocities.

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